x^2+18x=2x-64

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Solution for x^2+18x=2x-64 equation: 



x^2+18x=2x-64

We move all terms to the left:

x^2+18x-(2x-64)=0

We get rid of parentheses

x^2+18x-2x+64=0

We add all the numbers together, and all the variables

x^2+16x+64=0

a = 1; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{2}=-8$

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